Searched refs:nDay (Results 1 – 1 of 1) sorted by relevance
16296 int nDay; /* Number of days since 1st day of year */ in strftimeFunc() local16302 nDay = (int)((x.iJD-y.iJD+43200000)/86400000); in strftimeFunc()16306 sqlite3_snprintf(3, &z[j],"%02d",(nDay+7-wd)/7); in strftimeFunc()16309 sqlite3_snprintf(4, &z[j],"%03d",nDay+1); in strftimeFunc()
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