Searched refs:isIntersection (Results 1 – 1 of 1) sorted by relevance
563 public bool $isIntersection; variable in Type603 $isIntersection = false;624 $isIntersection = ($char === "&");633 return new Type($simpleTypes, $isIntersection);639 private function __construct(array $types, bool $isIntersection) { argument641 $this->isIntersection = $isIntersection;736 $typeSort = $this->isIntersection ? "intersection" : "union";777 $char = $this->isIntersection ? '&' : '|';2455 if ($this->type->isIntersection) {
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