Searched refs:isIntersection (Results 1 – 1 of 1) sorted by relevance
562 public bool $isIntersection; variable in Type602 $isIntersection = false;623 $isIntersection = ($char === "&");632 return new Type($simpleTypes, $isIntersection);638 private function __construct(array $types, bool $isIntersection) { argument640 $this->isIntersection = $isIntersection;735 $typeSort = $this->isIntersection ? "intersection" : "union";776 $char = $this->isIntersection ? '&' : '|';2444 if ($this->type->isIntersection) {
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