Searched refs:leap_days (Results 1 – 1 of 1) sorted by relevance
288 int leap_days = year - (mon <= 1); in time2epoch() local289 leap_days = ((leap_days / 4) - (leap_days / 100) + (leap_days / 400) in time2epoch()292 + leap_days + month_days_cumulative[mon] + mday - 1) * 24 in time2epoch()
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