Searched refs:bits28 (Results 1 – 1 of 1) sorted by relevance
219 uint32_t *bits28, *bits24; in _crypt_extended_init() local226 bits24 = (bits28 = bits32 + 4) + 4; in _crypt_extended_init()306 *il |= bits28[obit]; in _crypt_extended_init()308 *ir |= bits28[obit - 28]; in _crypt_extended_init()
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